Bob W asked:
The barium atom has an emission with wavelength 554 nm (green).
The barium atom has an emission with wavelength 554 nm (green).
so do i do
v=3.00* 10^8 / 554* 10^-9 which gives me 5.41-10^14?
how do i write that if that blank is frequency = ___sec^1? i dont get that
and next how to i find the energy? thank you!
your answer is correct 5.41*10^14s-1 or 5.41*10^14Hz
1Hz (hertz) is equal to 1s^-1
Your answer is right since wavelength = c/v. Rearranging, we get v = c / wavelength. The unit for frequency is 1/sec or sec^-1.
According to Planck’s equation, E = hv
where h = Planck’s constant = 6.626 x 10^-34 Joules-second = 6.626 x 10^-34 J-s
Since you’ve already computed for v, then you can solve for E.
E = (6.626 x 10^-34 J-s) x (5.41-10^14 / s) = 3.58 x 10^-19 J
The unit of energy is Joules (J).
=)